Ek's Home   |   Forum   |   Chat   |   Electrical Links   |  





Subject - Transformers
komaraiah how to improve the power factor from 0.55 to 0.95
Rated transformer is 500KVA At 60HP At Receiving end
At transformer side voltage is 440volts,At load side (Receving end)390volts Transformer to receiving end cable size is 4core 50 sq mm
Ed MacLaren The system power factor is determined by the type of load served.

In order to calculate the capacitor rating required to improve the PF, we would need to know the load voltage and current, the load kVA, or the load kW.


Ed
Ryan_J So, Ed MacLaren is in the house!!!

This site just gained a whole lot of knowledge. Welcome Ed, your expertise, which is second to none, will be much valued here. Its good to see you here.
cs409 Ryan,,,,stop that kissing up LOL
Scott Vickrey Wow, welcome aboard Ed.
cs409 instructor material,,thats always good to have......
Ed MacLaren You're too kind, guys.

This looks like an interesting forum.

I wonder where the originator of this thread, komaraiah, is? Power Factor, and PF correction, is one of my favorite topics.

Ed
komaraiah Dear Ed MacLaren
Thank you For Reply, Iam intrested to learn the power factor improvement. The load particulars are
Load volatage is 390volts
Load current is 120.5Amps
Load KW is 44.76KW
Load KVA is 81.38Kva
plz sena the calculation details easy way.
Once again thank you
Ed MacLaren First, a few basics -

a. The True Power (KW) and the Reactive Power (KVAR) required by the load are constant and will not change when Power Factor (PF) is improved.

b. Only the KVAR, and as a result of this, the KVA, supplied by the utility will be reduced by the correction of the PF.

c. The function of the capacitor bank is to supply all, or a portion of, the KVAR requirements of the load.

Below is an example calculation, using the values quoted by Mr komaraiah above.

Ed




JimmyDee This sure beats the way we use to do it. We would throw a 10 KVAR on it and check it out then work up from there. Aren't math and formulas great.
I'd like to see these formulas permanently posted in our, not yet created, Electrical Formula section.
Jim
komaraiah Thank you for neat explanation iam easily understand the problem
THANK YOU SO MUCH