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	Subject - determining 'Real Power' with an amp-meter beaverbazz Hello and thank you to those who responded to my last post. How can I determine 'real power [W]' from knowing each phases current and voltage? Some of the motors are operating at full load and the power factor on the nameplate should apply, but what about the motors that are not running at full load? I am trying to determine a wire horsepower (wHP=Real Power [watts]/746 [watts/hp]). My only tool is a multi meter...Is this even possible? From the aid I recieved here before I have a high delta leg (120-240-120). Is this a 'wye' with a 3 hot wire / 1 wire neutral? Anyways, if someone can explain how to get a real power from volts and amps at less then full load I would greatly appreciate it. Thanks in advance. Afterhrs What is it that you are trying to determine, and what is your application. If your load is constant, then you should be able to get in the ballpark if you can determine amperage and voltage. If your load is not constant, like say a press machine, then you will have a hard time getting a real time measurement. Regards, Jerry wareagle Beaver Real Power in KW = KVA x power factor. Amps x volts x 1.73 = KVA 3 phase and Amps x Volts for 1 phase You probably do not know the power factor so you can not make the caculation. You can assume a PF but it may not be correct. Using only a voltmeter and clip on amp meter you can only get the KVA.